1/2x^2-7x+20=0

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Solution for 1/2x^2-7x+20=0 equation: 


x in (-oo:+oo)

(1/2)*x^2-(7*x)+20 = 0

(1/2)*x^2-7*x+20 = 0

1/2*x^2-7*x+20 = 0

DELTA = (-7)^2-(1/2*4*20)

DELTA = 9

DELTA > 0

x = (9^(1/2)+7)/(1/2*2) or x = (7-9^(1/2))/(1/2*2)

x = 10 or x = 4

x in { 4, 10 }

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